How many grams of NaNo3 are required to saturate 200 grams of water at 10 degrees Celsius

162.0 g.

Explanation:

The solubility is the maximum amount of solute dissolved in a given amount of solvent to form saturated solution.

The solubility of NaNO₃ in 100.0 g of water at 10.0°C is 81.0 g / 100 g water.

Using cross multiplication:

81.0 g of NaNO₃ form saturated solution at 10.0°C in → 100.0 g of water.

? g of NaNO₃ form saturated solution at 10.0°C in → 200.0 g of water.

∴ The grams of NaNO₃ form saturated solution at 10.0°C in 200.0 g of water = (81.0 g) (200.0 g) / (100.0 g) = 162.0 g.