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14 November, 08:06

A chemist prepares a solution of aluminum sulfite by measuring out 109 umol of aluminum sulfite into a 350 mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mmol/L of the chemist's aluminum sulfite solution. Be sure your answer has the correct number of significant digits.

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  1. 14 November, 10:40
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    0.311 mmol/L

    Explanation:

    109 μmol = 109*10^ (-6) mol

    109*10^ (-6) mol = 109*10^ (-6) mol * (10^3 mmol/1mol) = 109*10^ (-3) mmol =

    =0.109 mmol

    350 mL = 0.350 L

    0.109 mmol/0.350 L = 0.311 mmol/L
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