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24 October, 02:21

What is the molarity of a solution made by dissolving 39.4 g of lithium chloride in enough water to make 1.59 l of solution?

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  1. 24 October, 05:30
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    Molar mass LiCl = 42.394 g/mol

    number of moles solute:

    n = mass of solute / molar mass

    n = 39.4 / 42.394

    n = 0.929 moles

    Therefore:

    Molarity = number of moles / volume (L)

    M = 0.929 / 1.59

    M = 0.584 mol/L
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