If the initial temperature of an ideal gas at 2.250 atm is 62.00 °C, what final temperature would cause the pressure to be reduced to 1.550 atm?

According to the ideal gas equation, the ratio of the initial pressure to the initial temperature should be equal to the ratio of the test pressure to the final tperature, i. e. P1T1=P2/T2

P1=2.250atm

P2=1.55atm

T1=335Kelvin (62°C+273)

T2=?

2.25atm/335K=1.55atm/T2

T2 = (1.55atm*335K) / 2.25

=230.778Kelvin

=-42.222°C