Assume that the partial pressure of sulfur dioxide, pso2, is equal to the partial pressure of dihydrogen sulfide, ph2s, and therefore pso2=ph2s. if the vapor pressure of water is 23 torr, calculate the equilibrium partial pressure of so2 (pso2 in the system at 298 k.

Given:

Sulfur dioxide and dihydrogen sulfide system

Vapor Pressure of water, H2O = 23 torr

P_SO2 = P_H2S

Temperature of the system = 298 K

Assume: Total pressure of the system is 1 atm = 760 torr

If partial pressure of SO2 is equal to the concentration of H2S, then,

760 = 0.5*PSO2 + 0.5PH2S

760 = PSO2