To what volume will a sample of gas expand if it is heated from 50.0∘c and 2.33 l to 500.0°c?

We can use Charle's law to solve this problem.

Charle's law says "at a constant pressure, the volume of a fixed amount of gas is directly proportional to its absolute temperature".

V α T

Where V is the volume and T is the temperature in Kelvin of the gas.

We can use this for two situations as,

V₁/T₁ = V₂/T₂

V₁ = 2.33 L

T₁ = (50 + 273) K = 323 K

V₂ = ?

T₂ = (500 + 273) K = 773 K

By applying the formula,

2.33 L / 323 K = V₂ / 773 K

V₂ = (2.33 L / 323 K) x 773 K

V₂ = 5.576 L

V₂ = 5.58 L

Hence, the volume of the gas at 500.0 °C will be 5.58 L.

Assumptions : 1. the pressure of the gas is a constant.

2. the gas has an ideal gas behavior.