Ask Question
15 May, 00:30

If a gas occupies 30 l at 1.3 atm and 300 k what volume will it occupy at stp

+3
Answers (2)
  1. 15 May, 00:37
    0
    Answer : Using t he ideal gas equation, which is;

    PV=nRT.

    Where, P = 1.3 atm, T = 300K.

    We can consider, n and R are constant.

    now, on comparing the gas at STP conditions (At standard pressure and temperature),

    P′ = 1 atm, and T′ = 273K;

    V′ = ?

    So, the ideal gas equation is modified as P′V′=nRT′.

    Dividing the equations, P′/P X V′/V=T′/T

    Therefore, (1 atm / 1.3 atm) X (V' / 30 L) = (273 K / 300 K)

    V' = ~ 20.9 L

    So, the volume of gas at STP will be ~ 20.9 L
  2. 15 May, 02:25
    0
    Let's assume that the given gas is an ideal gas.

    We can use combined gas law,

    PV/T = k (constant)

    Where, P is the pressure of the gas, V is volume of the gas and T is the temperature of the gas in Kelvin.

    For two situations, we can use that as,

    P₁V₁/T₁ = P₂V₂/T₂

    P₁ = 1.3 atm

    V₁ = 30 L

    T₁ = 300 K

    P₂ = Standard pressure = 1 atm

    V₂ = ?

    T₂ = Standard temperature = 273 K

    By applying the formula,

    1.3 atm x 30 L / 300 K = 1 atm x V₂ / 273 K

    V₂ = (1.3 atm x 30 L x 273 K) / (300 K x 1 atm)

    V₂ = 35.49 L

    Hence, the volume of the gas at STP is 35.49 L.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If a gas occupies 30 l at 1.3 atm and 300 k what volume will it occupy at stp ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers