The above shows a sealed flask filled with oxygen gas. The gas has a temperature of 300.00 K and a pressure of 101 kPa. If the temperature increases to 320.0 K, what is the new pressure of the oxygen gas

107.73KPa

Explanation:

Data obtained from the question include:

T1 (initial temperature) = 300K

P1 (initial pressure) = 101KPa

T2 (final temperature) = 320K

P2 (final pressure) = ?

Using the the equation P1/T1 = P2/T2, the final pressure (i. e the new pressure) of the gas can be obtained as follow:

P1/T1 = P2/T2

101/300 = P2/320

Cross multiply to express in linear form as shown below:

300 x P2 = 101 x 320

Divide both side by 300

P2 = (101 x 320) / 300

P2 = 107.73KPa

Therefore, the new pressure of the oxygen gas is 107.73KPa