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30 April, 06:47

2Mg + O2 → 2MgO How many grams of MgO are produced when 40.0 grams of O2 react completely with Mg?

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  1. 30 April, 09:28
    0
    101 g

    Explanation:

    M (O2) = 2g*16.0 = 32.0 g / mol

    M (MgO) = 24.3 + 16.0 = 40.3 g/mol

    2 Mg + O2 → 2MgO

    from reaction 1 mol 2 mol

    from reaction 1 mol*32.0 g/mol 2 mol*40.3 g/mol

    given 40 g x g

    1 mol*32.0 g/mol - - - 2 mol*40.3 g/mol

    40 g - - - x g

    x = (40*2*40.3) / (1*32.0) = 100.75 g ≈ 101 g
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