How many molecules are in 95.75 g of Calcium chloride?

5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.

Explanation:

It is known that every 1.0 mole of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³). We need to calculate the no. of moles in 95.75 g of CaCl₂ using the relation:

n = mass/molar mass = (95.75 g) / (110.98 g/mol) = 0.86 mol.

Using cross multiplication:

1.0 mole of CaCl₂ contains → 6.022 x 10²³ molecules.

0.86 mole of CaCl₂ contains →? molecules.

∴ 95.75 g of CaCl₂ (0.86 mole) contain = (0.86 mol) (6.022 x 10²³) = 5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.