If 30 g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the percent yield of the experiment?

Percent yield of NaCl = 20.85%

Explanation:

Given dа ta:

Mass of HCl = 30 g

Actual yield of NaCl = 10 g

Percent yield of NaCl = ?

Solution:

Chemical equation:

HCl + NaOH → NaCl + H₂O

Moles of HCl:

Number of moles = mass / molar mass

Number of moles = 30 g / 36.5 g/mol

Number of moles = 0.82 mol

Now we will compare the moles of HCl with NaCl

HCl : NaCl

1 : 1

0.82 : 0.82

Theoretical yield:

Mass = number of moles * molar mass

Mass = 0.82 mol * 58.5 g/mol

Mass = 47.97 g

Percentage yield:

Formula:

Percent yield = Actual yield / theoretical yield * 100

Now we will put the values.

Percent yield = 10 g / 47.97 g * 100

Percent yield = 20.85%