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5 July, 09:09

If 468mL of gas is measured at 0.83atm, then what volume would the gas occupy at 1.05atm?

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  1. 5 July, 12:33
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    Answer: V = 369.94mL

    Explanation:

    Applying Boyle's law

    P1V1=P2V2

    P1 = 0.83atm, V1 = 468mL, P2 = 1.08atm V2=?

    Substitute into above

    0.83 * 468 = 1.08 * V2

    V2 = 369.9mL
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