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18 January, 18:46

What is the pressure, in atmospheres, of a 0.108-mol sample of helium gas at a temperature of 20.0°C if its volume is 0.505 L?

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  1. 18 January, 22:10
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    P = 5.14ATM

    Explanation:

    Number of moles = 0.108moles

    Temperature (T) = 20°C = 20 + 273.15 = 293.15K

    Volume V = 0.505L.

    Pressure (P) = ?

    R = 0.082J/mol. K

    From ideal gas equation,

    PV = nRT

    P = nRT / V

    P = (0.108 * 0.082 * 293.15) / 0.505

    P = 2.596 / 0.505

    P = 5.14ATM

    The pressure of the gas is 5.14ATM
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