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15 February, 16:30

What volume does 2.25g of nitrogen gas, N2, occupy at 273 Celsius and 1.02 atm

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  1. 15 February, 19:01
    0
    0.126 Liters

    Explanation:

    V = mRT / mmP

    First, convert the 2.25g of Nitrogen gas into moles. (m in the equation above)

    2.25g x 1 mole / 28.0g = 0.08036 moles = m

    28.0g = mm

    Next, convert the 273 Celsius into Kelvin. (T in the equation above)

    273 Celsius + 273.15 = 546.15K = T

    R = 0.08206L*atm/mol*K

    (Quick Note: The R changes depending on the Pressure Unit so do not use this number every time.)

    Now, plug everything into the equation.

    V = (0.08036) (0.08206) (546.15) / (28.0) (1.02)

    V = 0.126 L
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