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23 March, 09:45

What mass of each gas is present in a 1.15 - l sample of this mixture at 25.0 ∘c?

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  1. 23 March, 12:49
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    total pressure = 666/760=0.876 atm

    moles gas = 0.876 x 1.10 L / 0.08206 x 298 K=0.0394

    moles N2 / 0.0394 = 330 / 666

    moles N2 = 0.0195

    mass N2 = 0.0195 x 28.0134 g/mol = 0.546 g

    moles O2 / 0.0394 = 126/666

    moles O2 = 0.00745

    mass O2 = 0.00745 x 32 g/mol=0.239 g

    moles He / 0.0394 = 210 / 666

    moles He = 0.0124

    mass He = 0.0124 x 4 g/mol=0.0497 g
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