What is the molarity of an aqueous solution containing 40.0 g of glucose (C6H12O6) in 1.5 L of solution?

The molarity of the solution is 0.148 mol/L.

Explanation:

Molarity of a substance in a solution is the number of moles of that substance per liter of the solution.

In this question first we have to find out the number of moles of glucose:

Number of moles = Mass in grams/molar mass of the substance.

By putting the values in the above formula:

Number of moles = 40 / 180 = 0.2223 mol

Now divide the number of moles with volume of the solution:

Molarity = 0.2223/1.5 = 0.148 mol/L.