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17 January, 16:17

A container holds 7.2 L of nitrogen at 25 °C. What will be its volume if the temperature increases

to 70 °C?

Hint: Use Charles' Law - (V/T1) = (V2/T2)

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Answers (1)
  1. 17 January, 16:50
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    Answer: 8.23L

    Explanation:

    Initial volume of nitrogen V1 = 7.2 L

    Initial temperature T1 = 25 °C

    Convert temperature in Celsius to Kelvin

    (25 °C + 273 = 298K)

    New volume V2 = ?

    New Temperature T2 = 70 °C

    (70°C + 273 = 343K)

    Since, volume and temperature are involved while pressure is constant, apply the formula for Charles' Law:

    (V1/T1) = (V2/T2)

    7.2L/298K = V2/343K

    0.024 = V2/343K

    To get V2, cross multiply

    V2 = 0.024 x 343

    V2 = 8.23L

    Thus, the new volume of nitrogen is 8.23 liters
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