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23 February, 00:25

What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl) ?

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  1. 23 February, 02:49
    0
    The mass of NaCl formed is 8.307 grams

    calculation

    step 1: write the equation for reaction

    Na₂CO₃ + 2HCl → 2 NaCl + CO₂ + H₂O

    Step 2: find the moles of Na₂CO₃

    moles = mass/molar mass

    The molar mass of Na₂CO₃ is = (23 x2) + 12 + (16 x3) = 106 g/mol

    moles = 7.5 g/106 g/mol = 0.071 moles

    Step 3: use the mole ratio to determine the mole of NaCl

    Na₂CO₃:NaCl is 1:2 therefore the moles of NaCl = 0.07 x2 = 0.142 moles

    Step 4: calculate mass of NaCl

    mass = moles x molar mass

    the molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

    mass = 0.142 moles x 58.5 g/mol = 8.307 grams
  2. 23 February, 03:55
    0
    What mass of sodium chloride (NaCl) forms when 7.5 g of sodium carbonate (Na2CO3) reacts with a dilute solution of hydrochloric acid (HCl) ?

    Next, cancel like terms and units. Which of the following shows the correct terms and units canceled?

    First Option
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