A flask contains 0.83molof neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the volume of the neon gas?

V = 56.72 L

Explanation:

Given dа ta:

Number of mole of neon gas = 0.83 mol

Temperature = 35°C

Pressure = 0.37 atm

Volume of gas = ?

Solution;

Temperature = 35°C (35+273 = 308K)

Formula:

PV = nRT

R = general gas constant = 0.0821 atm. L/mol. K

Now we will put the values in formula.

V = nRT/P

V = 0.83 mol * 0.0821 atm. L/mol. K * 308K / 0.37 atm

V = 20.99 L / 0.37

V = 56.72 L