What is the de Broglie wavelength, in cm, of a 11.0-g hummingbird flying at 1.20 x 10^2 mph?

(1 mile=1.61 km.)

Answer:1.123 x 10^-31cm

Explanation:

mass of humming bird = 11.0g

speed = 1.20x10^2mph

but I mile = 1.6m

1km=1000

I mile = 1.6x10^3m

1.20x10^2mph = 1.6x10^3m / 1mile x at 1.20 x 10^2

=1.932 x10^5m

recall that

1 hr = 60 min

1 min=60 secs, 1hr=3600s

Speed = distance / time

=1.932 x10^5 / 3600 = 5.366 x 10 ^1 m/s

m = a 11.0g = 11.0 x 10^-3kg

h=6.626*10^-34 (kg*m^2) / s

Wavelength = h/mu

= 6.626*10^-34 / (11 x 10^-3 x 5.366x 10^1)

6.63x10^-34 / 590.26x 10 ^-3 = 1.123 x10^-33m

but 1m = 100cm

1.123 x 10 ^-33 x 100 = 1.123 x 10^-31cm

de broglie wavelength of humming bird = 1.123 x 10 ^-31cm