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29 July, 01:35

Now consider the reaction when 45.0 g NaOH have been added. What amount of NaOH is this, and what amount of FeCl3 can be consumed by it?

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  1. 29 July, 05:15
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    The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.

    The mass of NaOH is 45 g

    The molar mass of NaOH = 40 g/mol

    The moles of NaOH = mass / molar mass

    = 45 / 40

    = 1.125

    Thus, 1.125 mol NaOH is available

    3 NaOH + FeCl₃ ⇒ Fe (OH) ₃ + 3NaCl

    3 mol of NaOH react with 1 mol of FeCl₃

    1.125 moles of NaOH will react with x moles of FeCl₃

    x = 1.125 / 3

    x = 0.375 mol

    0.375 mol FeCl₃ can take part in reaction

    The molar mass of FeCl₃ is 162 g/mol

    The mass of FeCl₃ = moles * mass

    = 0.375 * 162

    = 60.75 g

    Thus, the amount of FeCl₃, which can be consumed is 60.75 g
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