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21 March, 01:56

The aluminum foil on a certain roll has a total area of 18.5 m squared and a mass of 1275 g. Using density of 2.7 g per cubic centimeter for aluminum, determine the thickness in millimeters of the aluminum foil.

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  1. 21 March, 02:38
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    Answer is: the thickness is 0.0256 millimeters.

    m (Al) = 1275 g; mass of aluminium foil.

    d (Al) = 2.7 g/cm³; density of aluminium foil.

    V (Al) = m (Al) : d (Al).

    V (Al) = 1275 g : 2.7 g/cm³.

    V (Al) = 472.2 cm³ : 10⁶ cm³/m³.

    V (Al) = 0.000472 m³, volume of aluminum foil.

    V (Al) = P · l (thickness).

    l = 0.000472 m³ : 18.5 m².

    l = 0.0000256 m · 1000 mm/m.

    l = 0.0256 mm.
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