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27 August, 02:48

A chemist carefully measures the amount of heat needed to raise the temperature of a 278.0g sample of C5H12S from 0.8degree celsius to 15.9 degree celsius. The experiment shows that 8.46X10^3J of heat are needed. What can the chemist report for the molar heat capacity of C5H12S? Be sure your answer has the correct number of significant digits.

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  1. 27 August, 06:08
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    The answer to your question is C = 2.01 J/g°C

    Explanation:

    Data

    mass = m = 278 g

    Temperature 1 = T1 = 0.8°C

    Temperature 2 = T2 = 15.9 °C

    Heat = Q = 8.46 x 10³ J

    Heat capacity = C = ?

    Process

    1. - Write the formula to calculate the heat

    Q = mC (T2 - T1)

    2. - Solve for C

    C = Q / m (T2 - T1)

    3. - Substitution

    C = 8.46 x 10³ / 278 (15.9 - 0.8)

    4. - Simplification

    C = 8.46 x 10³ / 4197.8

    5. - Result

    C = 2.01 J/g°C
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