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30 March, 20:01

Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).

Upper C upper O (g) plus 3 upper H subscript 2 (g) double-headed arrow upper C upper H 4 (g) plus upper H subscript 2 upper O (g).

The reaction is at equilibrium at 1,000 K. The equilibrium constant of the reaction is 3.90. At equilibrium, the concentrations are as follows.

[CO] = 0.30 M

[H2] = 0.10 M

[H2O] = 0.020 M

What is the equilibrium concentration of CH4 expressed in scientific notation?

.0059

5.9 x 10-2

0.059

5.9 x 102

+5
Answers (1)
  1. 30 March, 22:24
    0
    5.9x10^-2 M

    Explanation:

    Step 1:

    Data obtained from the question. This includes the following:

    Concentration of CO, [CO] = 0.30 M

    Concentration of H2, [H2] = 0.10 M

    Concentration of H2O, [H2O] = 0.020 M

    Equilibrium constant, K = 3.90

    Concentration of CH4, [CH4] = ... ?

    Step 2:

    The balanced equation for the reaction. This is given below:

    CO (g) + 3H2 (g) CH4 (g) + H2O (g)

    Step 3:

    Determination of the concentration of CH4.

    The expression for equilibrium constant of the above equation is given below:

    K = [CH4] [H2O] / [CO] [H2]^3

    3.9 = [CH4] x 0.02 / 0.3 x (0.1) ^3

    Cross multiply to express in linear form

    [CH4] x 0.02 = 3.9 x 0.3 x (0.1) ^3

    Divide both side by 0.02

    [CH4] = 3.9 x 0.3 x (0.1) ^3 / 0.02

    [CH4] = 5.9x10^-2 M

    Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M
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