A gas occupies 12.3 liters at a temperature of 40.0k what is the volume when the temperature is increased to 60.0k

18.45L

Explanation:

V1 = 12.3L

T1 = 40K

T2 = 60K

V2 = ?

This question involves the use of Charles law which states that the volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant.

Mathematically,

V = kT k = V/T

V1 / T1 = V2 / T2 = V3 / T3 = ... = Vn / Tn

V1 / T1 = V2 / T2

V2 = (V1 * T2) / T1

V2 = (12.3 * 60) / 40

V2 = 18.45L

The final volume of the gas is 18.45L