Having 23.26 g of NaOH and 18.73 g of HCl what will be the limiting reactant

NaOH + HCl = > NaCl + H2O

1 mol of NaOH react with 1 mol of HCL

The molecular mass of NaOH is 39.997

The molecular mass of HCl is 36.46

Moles of HCl

=18.73/36.46

=0.5137

Mole of NaOH

=23.26/39.997

=0.5815

moles of NaOH >moles of HCl

so there are not enough HCl

the answer is HCl