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24 November, 00:27

Determine the molarity of a solution made by dissolving 8.36 g of MgCl2 in water where the final volume of the solution is 500.0 mL.

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  1. 24 November, 03:35
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    Answer is: the molarity of the solution is 0.176 M.

    m (MgCl₂) = 8.36 g; mass of magnesium chloride.

    M (MgCl₂) = 95.21 g/mol; molar mass of magnesium chloride.

    n (MgCl₂) = m (MgCl₂) : M (MgCl₂).

    n (MgCl₂) = 8.36 g : 95.21 g/mol.

    n (MgCl₂) = 0.0878 mol; amount of magnesium chloride.

    V = 500 mL : 1000 mL/L.

    V = 0.5 L; volume of the solution.

    c (MgCl₂) = n (MgCl₂) : V.

    c (MgCl₂) = 0.0878 mol : 0.5 L.

    c (MgCl₂) = 0.176 mol/L; the molarity of the solution.
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