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23 March, 01:18

If a certain gas occupies a volume of 19 L when the applied pressure is 9.5 atm, find the pressure when the gas occupies a volume of 4.8 L

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  1. 23 March, 05:08
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    Answer: 37.6 atm

    Explanation:

    Given that,

    Initial volume of gas (V1) = 19L

    Initial pressure of gas (P1) = 9.5 atm

    Final volume of gas (V2) = 4.8L

    Final pressure of gas (P2) = ?

    Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

    P1V1 = P2V2

    9.5 atm x 19L = P2 x 4.8L

    180.5 atm•L = 4.8L•P2

    Divide both sides by 4.8L

    180.5 atm•L/4.8L = 4.8L•P2/4.8L

    37.6 atm = P2

    Thus, the final pressure is 37.6 atmospheres.
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