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31 January, 14:53

What is the temperature (°c) of 2.48 moles of gas stored in a 30.0 l container at 1559 mm hg? (r = 0.0821 l atm / mol k) ?

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  1. 31 January, 16:48
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    Answer is: the temperature is 28.9°C.

    n = 2.48; amount of the gas.

    V = 30.0 L; volume of the gas.

    p = 1559 mmHg : 760 mmHg/atm.

    p = 2.05 atm; pressure of the gas.

    R = 0.0821 L·atm/mol·K.

    Ideal gas law: p·V = n·R·T.

    T = p·V : (n·R).

    T = 302.05 K - 273.15.

    T = 28.9°C; temperature of the gas.
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