C3H2 + 502 + 3 CO2 + 4H20

6) Determine the number of moles of water produced from 1.55 moles of propane (CH3).

Answer: 6.2 moles

Explanation:

C3H8 (g) + 5O2 (g) - --> 3CO2 (g) + 4H2O (g)

The balanced equation above shows the combustion of propane, C3H8 in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O

The mole ratio of combustion are as follows:

1 mole of C3H8 react to produce 4 moles of H2O

1.55 mole of C3H8 will react to produce Z moles of H2O

To get the value of Z, cross multiply

Z x 1 mole = 1.55 mole x 4 mole

Z = 6.2 moles

Thus, 6.2 moles of water will be produced from 1.55 moles of propane