If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP

Question

Chemistry

Guest

1 May, 13:18

If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP

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Answers (1)

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Ernest Russell · Answer 1

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l Volume 2 = ?

Temperature 1 = T1 = 479°K Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa Pressure 2 = P2 = 101.325 Kpa

Process

1. - Use the combined gas law to solve this problem

P1V1/T1 = P2V2/t2

-Solve for V2

V2 = P1V1T2 / T1P2

2. - Substitution

V2 = (300) (240) (293) / (479) (101.325)

3. - Simplification

V2 = 21096000 / 48534.675

4. - Result

V2 = 434.7 l