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17 December, 20:45

A gas occupying a volume of 425 mL at a pressure of 2 atm is allowed to expand until the pressure reaches 588 mmHg. What is the final volume in mL?

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  1. 17 December, 22:37
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    Answer: 1098.6 mL

    Explanation:

    Given that,

    Initial volume of gas (V1) = 425mL

    Initial pressure of gas (P1) = 2 atm

    [Since final pressure is given in mmHg, convert 2 atm to mmHg

    1 atm = 760 mmHg

    2 atm = 2 x 760 = 1520 mmHg]

    Final volume of gas (V2) = ?

    Final pressure of gas (P2) = 588 mmHg

    Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

    P1V1 = P2V2

    1520 mmHg x 425mL = 588 mmHg x V2

    646000 mmHg•mL = 588 mmHg•V2

    Divide both sides by 588 mmHg

    646000 mmHg•mL/588 mmHg = 588 mmHg•V2/588 mmHg

    1098.639 mL = V2

    Round the 1098.639 to the nearest tenth, hence it becomes 1098.6

    Thus, the final volume of the gas is 1098.6 mL
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