When the pressure that a gas exerts on a sealed container changed from 32.6 psi to ___ psi, the temperature changes from 735 k to 1035 k?

45.91 psi.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

P₁T₂ = P₂T₁

P₁ = 32.6 psi, T₁ = 735.0 K.

P₂ = ? psi, T₂ = 1035.0 K.

∴ P₂ = P₁T₂/T₁ = (32.6 psi) (1035.0 K) / (735.0 K) = 45.91 psi.