In a lab, 2.20 L of gas is collected over water at a temperature of 30°C and a total pressure of 735.43 mmHg. Find the volume that the dry nitrogen of gas would occupy at STP.

V₂ = 1.9 L

Explanation:

Given dа ta:

Initial volume of gas = 2.20 L

Temperature = 30°C (30+273 = 303 K)

Initial pressure = 735.43 mmHg (735.43 / 760 = 0.97 atm)

Final volume of gas = ?

Final temperature = standard = 273 K

Final pressure = standard = 1 atm

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂ / T₁ P₂

V₂ = 0.97 atm * 2.20 L * 273 K / 303 K * 1 atm

V₂ = 582.58 atm. L. K / 303 k. atm

V₂ = 1.9 L