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14 July, 14:18

How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C?

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  1. 14 July, 15:54
    0
    550 J

    Explanation:

    The formula for the amount of heat (q) released by the copper is

    q = mCΔT

    dа ta:

    n = 0.762 mol

    C = 0.386 J°C⁻¹g⁻¹

    T_i = 81.6 °C

    T_f = 52.2 °C

    Calculations:

    (a) Mass of copper

    /text{Mass} = / text{0.762 mol} / times / dfrac{/text{63.55 g}}{/text{1 mol}} = / text{48.43 g}

    (b) ΔT

    ΔT = 81.6 °C - 52.2 °C = 29.4 °C

    (c) q

    q = mCΔT = 48.43 g * 0.386 J·°C⁻¹g⁻¹ * 29.4 °C = 550 J

    The amount of heat released by the copper is 550 J.
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