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11 February, 07:18

What volume is occupied by 8.7 g of chlorine gas, Cl2, at 23°C and 1.15 atm pressure

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  1. 11 February, 10:12
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    V = 5.17L

    Explanation:

    Mass of gas = 8.7g

    T = 23°C = (23 + 273.15) K = 296.15K

    P = 1.15 atm

    V = ?

    R = 0.082atm. L / mol. K

    From ideal gas equation

    PV = nRT

    P = pressure of the gas

    V = volume of the gas

    n = no. Of moles

    R = ideal gas constant

    T = temperature of the gas

    no of moles = mass / molar mass

    Molar mass of Chlorine = 35.5g / mol

    No. Of moles = 8.7 / 35.5

    No. Of moles = 0.245 moles

    PV = nRT

    V = nRT / P

    V = (0.245 * 0.082 * 296.15) / 1.15

    V = 5.9496 / 1.15

    V = 5.17L

    The volume of the gas is 5.17L
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