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13 November, 21:51

How many kilojoules of heat are absorbed when 2.00 L of water is heated from 19*C to 80*C? (Show all work including the equation you use to solve)

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  1. 13 November, 23:05
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    The answer to your question is 510.7 kJ

    Explanation:

    Data

    Q = ?

    Volume = 2 L

    Temperature 1 = T1 = 19°C

    Temperature 2 = T2 = 80°C

    Specific heat = 4.186 J/kg°C

    Density of water = 1 g/ml

    Equation

    Q = mC (T2 - T1)

    Process

    1. - Calculate the mass of water

    mass = density x volume

    mass = 1 x 2000

    mass = 2000 g

    2. - Substitute values in the Heat formula

    Q = (2000) (4.186) (80 - 19)

    -Simplification

    Q = (2000) (4.186) (61)

    -Result

    Q = 510692 J or 510.7 kJ
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