Ask Question
19 April, 09:23

A certain element x has four isotopes. 0.5600% of x has a mass of 83.91343 amu. 9.860% of x has a mass of 85.90927 amu. 7.000% of x has a mass of 86.90890 amu. 82.58% of x has a mass of 87.90562 amu. What is the average atomic mass of element x?

+5
Answers (2)
  1. 19 April, 12:52
    0
    solution:

    Find the average of atomic weight is

    (0.0056 x 83.91343) + (0.098860 x 85.90927) + (0.07x86.90890) + (0.8258x87.90562) = 87.61665 amu
  2. 19 April, 13:07
    0
    Average Atomic Weight (X) = 87.638974 amu

    Explanation:

    To find the average atomic weight of an unknown element that exhibit multiple isotopes is given by:

    Average Atomic Weight = Percentage of given isotope in the mass spectrum x The corresponding atomic weight of given isotope

    Average Atomic Weight (X) = [0.0056 x 83.91343] + [0.098860 x 85.90927] + [0.07 x 86.90890] + [0.8258 x 87.90562] = 87.638974 amu
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A certain element x has four isotopes. 0.5600% of x has a mass of 83.91343 amu. 9.860% of x has a mass of 85.90927 amu. 7.000% of x has a ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers