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9 September, 20:44

A balloon has a volume of 3.0 L at room temperature (27oC). At what temperature would the balloon have a volume of 4.0L?

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  1. 10 September, 00:21
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    Answer: 400K

    Explanation:

    Given that,

    Original volume of balloon V1 = 3.0L

    Original temperature of balloonT1 = 27°C

    Convert the temperature in Celsius to Kelvin

    (27°C + 273 = 300K)

    New volume of balloon V2 = 4.0L

    New temperature of balloon T2 = ?

    Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

    V1/T1 = V2/T2

    3.0L/300K = 4.0L/T2

    To get the value of T2, cross multiply

    3.0L x T2 = 4.0L x 300K

    3.0LT2 = 1200LK

    Divide both sides by 3.0L

    3.0LT2/3.0L = 1200LK/3.0L

    T2 = 400K

    Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.
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