At what pressure would 0.150 mole of nitrogen gas

at 23.0°C occupy 8.90 L?

The answer to your question is P = 0.40 atm

Explanation:

Data

number of moles = 0.15

temperature = 23°C

volume = 8.9 L

constant (R) = 0.082 atm L / mol°K

pressure = ?

Process

1. - Use the ideal gas formula to solve this problem

Formula

PV = nRT

-Solve for P

P = nRT / V

2.-Convert temperature to °K

Temperature = 23 + 273 = 296°K

3. - Substitution

P = (0.15 x 0.082 x 296) / 8.9

4. - Simplification

P = 3.641 / 8.9

5. - Result

P = 0.40 atm