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24 August, 09:56

How many grams of CaCl2 will be required in order to make a 60mL solution with the strength of 4M? M = mol solute / L of solution

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  1. 24 August, 12:46
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    26.6 g of CaCl₂ are required to make a 4M solution

    Explanation:

    4 M = Molarity of the solution

    This is a type of concentratrion for solutions, that indicates the moles of solute in 1L of solution.

    Solution's volume = 60 mL

    We need to convert the volume from mL to L → 60 mL. 1L / 1000mL = 0.060L

    Molarity = mol / volume (L) → Molarity. volume (L) = mol

    4 M. 0.060L = 0.24 mol of solute

    Let's convert the moles to mass → Molar mass CaCl₂

    0.24 mol. 110.98 g / 1mol = 26.6 g
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