How many grams of solute are in 250mL of 2.0M of CaCi2?

How many grams of solute are in 500.0 mL of a 4.4M solution of K2SO4?

1) 55.49 g.

2) 383.37 g.

Explanation:

Molarity is the no. of moles of solute in a liter of the solvent.

Molarity (M) = (n of solute) / (Volume of the solution (L)) = (mass/molar mass) solute x (1000/V of the solution (ml))

1) How many grams of solute are in 250 mL of 2.0 M of CaCl₂?

∵ M = (mass/molar mass) CaCl₂ x (1000/V of the solution (ml))

M of CaCl₂ = 2.0 M, V of the solution = 250.0 mL, molar mass of CaCl₂ = 110.98 g/mol.

∴ mass of CaCl₂ = (M) (V of the solution (ml)) (molar mass of CaCl₂) / 1000 = (2.0 M) (250.0 mL) (110.98 g/mol) / (1000) = 55.49 g.

2) How many grams of solute are in 500.0 mL of a 4.4 M solution of K₂SO₄?

∵ M) = (mass/molar mass) K₂SO₄ x (1000/V of the solution (ml))

M of CaCl₂ = 4.4 M, V of the solution = 500.0 mL, molar mass of K₂SO₄ = 174.259 g/mol.

∴ mass of K₂SO₄ = (M) (V of the solution (ml)) (molar mass of K₂SO₄) / 1000 = (4.4 M) (500.0 mL) (174.259 g/mol) / (1000) = 383.37 g.