when 22 grams of water undergoes a temeprature change from 35 ˚C to 65 ˚C, how much energy does the water absorb? The specific heat of water is 4.184.

Answer: 2761.44 joules

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of oil = 22g

C = 4.184Jg°C

Φ = (Final temperature - Initial temperature)

= 65°C - 35°C = 30°C

Then, Q = MCΦ

Q = 22g x 4.184Jg°C x 30°C

Q = 2761.41 Joules

Thus, water absorb 2761.44 joules of heat.