Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott traveled 10. Calculate each person's speed and tell who rode faster. (s=d/t) Question 6 options:

Question

Chemistry

Isai Russell

20 January, 16:56

Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott traveled 10. Calculate each person's speed and tell who rode faster. (s=d/t) Question 6 options:

+2

Answers (2)

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Demetrius Church · Answer 1

Answer is: Scott rode faster than Jill.

t (Jill, Scott) = 30 min : 60 min/h.

t (Jill, Scott) = 0.5 h; Jills and Scott time.

d (Jill) = 5 km; Jills traveled distance.

s (Jill) = d (Jill) : t (Jill).

s (Jill) = 5 km : 0.5 h.

s (JIll) = 10 km/h; Jills speed.

s (Scott) = 10 km : 0.5 h.

s (Scott) = 20 km/h; speed of Scott.

Mattie Navarro · Answer 2

I believe that the answer is B. Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h. Because Jill had only gone 5 kilometers vs Scott going a full 10 kileters double what Jill had went.

Have a nice day!