Ask Question
28 July, 06:29

A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?

+4
Answers (1)
  1. 28 July, 09:51
    0
    On the basis of the given dа ta:

    Volume (V) is 37.5 L

    Temperature (T) is 307 K

    Pressure (P) is 1.25 atm

    In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K

    n = PV / RT

    n = 1.25 atm * 37.5 L / 0.0821 Latm/mol/K * 307 K

    n = 1.85 mol
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers