A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?

Question

Chemistry

Medina

28 July, 06:29

A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?

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Answers (1)

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Hale · Answer 1

On the basis of the given dа ta:

Volume (V) is 37.5 L

Temperature (T) is 307 K

Pressure (P) is 1.25 atm

In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K

n = PV / RT

n = 1.25 atm * 37.5 L / 0.0821 Latm/mol/K * 307 K

n = 1.85 mol