At a certain temperature, the pHpH of a neutral solution is 7.45. What is the value of KwKwK_w at that temperature? Express your answer numerically using two significant figures. View Available Hint (s)

The value of Kw is 1.26 * 10^-15

Explanation:

Step 1: Data given

The pH of the neutral solution = 7.45

pH = - log[H+]

Kw = [OH-][H+]

Step 2: Calculate [H+]

pH = 7.45

-log[H+] = 7.45

[H+] = 10^-7.45

[H+] = 3.55 * 10^-8 M

Step 3: Calculate [OH-]

Since pH and pOH are equal in our neutral solution so are [H+] = [OH-]

[OH-] = 3.55 * 10^-8 M

Step 4: Calculate Kw

Kw = [H]*[OH]

Kw = 3.55 * 10^-8 M * 3.55 * 10^-8 M

Kw = (3.55 * 10^-8) ²

Kw = 1.26 * 10^-15

The value of Kw is 1.26 * 10^-15