The average rate of disappearance of ozone in the reaction 2o3 (g) → 3o2 (g) is found to be 7.25*10-3 atm over a certain interval of time. what is the rate of appearance of o2 during this interval?

Answer;

1.0875 x 10-2 atm

Explanation;

2O3 (g) → 3O2 (g)

rate = - (1/2) ∆[O3]/∆t = + (1/3) ∆[O2) / ∆t

The average rate of disappearance of ozone ... is found to

be 7.25 * 10-3 atm over a certain interval of time.

This means (ignoring time)

∆[O3]/∆t = - 7.25 * 10^-3 atm

(it is disappearing, thus the negative sign)

rate = - (1/2) ∆[O3]/∆t

rate = - (1/2) * (-7.25 * 10^-3 atm)

= 3.625 * 10^-3 atm

Now use the other part of the expression:

rate = + (1/3) ∆[O2) ∆t

3.625 * 10-3 atm = + (1/3) ∆[O2) / t

∆[O2) / ∆t = (3) * (3.625 * 10^-3 atm)

= 1.0875 x 10-2 atm over the same time interval