I2 is produced by the reaction of 0.4235 mol of CuCl2 according to the following equation: 2CuCl2+4KI 2CuI+4KCl+I2

React with 0.847 mol of KI

Produce:

0.4235 mol of CuI

0.847 mol of KCl

0.21175 moles de I2

Explanation:

2CuCl2 + 4KI produce 2CuI + 4KCl + I2

The stoichiometric coefficients give us the relationship in moles:

2 mol of CuCl2 ... react whit ... 4 mol of KI

0.4235 mol of CuCl2 ... react whit ... X = 0.847mol of KI

2 mol of CuCl2 ... produce ... 2 mol of CuI

0.4235 mol of CuCl2 ... produce ... X=0.4235 mol of CuI

2 mol of CuCl2 ... produce ... 4 mol of KCl

0.4235 mol of CuCl2 ... produce ... X = 0.847 mol of KCl

2 mol of CuCl2 ... produce ... 1 mol of I2

0.4235 mol of CuCl2 ... produce ... X = 0.21175 moles de I2

If you need to know the mass that is produced you just have to multiply the moles by the molecular mass