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20 December, 04:55

2. What is the mass of 16.3 L of helium gas?

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Answers (2)
  1. 20 December, 07:27
    0
    (16.3 L) / (22.414 L/mol) x (4.0026 g He/mol) = 2.91 g
  2. 20 December, 08:03
    0
    mass = 2.91 grams

    Explanation:

    Base on Avogadro's law, At standard temperature and pressure the molar volume is the same for an ideal gas. Base on this practical principle the molar volume of gases is 22.4 dm³ per mol.

    Since the molar mass of 1 mol of helium is 4.002602, this simply means the molar volume which is 22.4 dm³ = 4.002602.

    Convert dm³ to liter,

    1 dm³ (cubic decimeter) = 1 liter

    22.4 dm³ = 22.4 liter

    Therefore,

    if 22.4 = 4.002602

    16. 3 = mass of the helium gas

    cross multiply

    mass = 16.3 * 4.002602/22.4

    mass = 65.2424126/22.4

    mass = 2.91260770536 grams

    mass = 2.91 grams
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