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7 July, 08:48

The specific heat of a certain type of metal is 0.128j / (g. c). What is the final temperature if 305. J of heat is added to 72.7g of the metal initially at 20.0°C?

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  1. 7 July, 11:20
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    E answer is - 60.57 = - 60.6 KJ.

    CaC2 (s) + 2 H2O (l) - - - > Ca (OH) 2 (s) + C2H2 (g) H = - 127.2 KJ

    Hf C2H2 = 226.77

    Hf Ca (OH) 2 = - 986.2

    Hf H2O = - 285.83

    Now,

    add them up. 226.77 - 986.2 + (2*285.83) = - 187.77

    Add back the total enthalpy that is given in the question

    -187.77+127.2 = - 60.57
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